(x)=x^2-4x+10

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Solution for (x)=x^2-4x+10 equation: 



(x)=x^2-4x+10

We move all terms to the left:

(x)-(x^2-4x+10)=0

We get rid of parentheses

-x^2+x+4x-10=0

We add all the numbers together, and all the variables

-1x^2+5x-10=0

a = -1; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·(-1)·(-10)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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